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To simplify the above expressions, start by expanding the binomials Note that we can expand the (ab)^3 , (bc)^3 , and (ca)^3 using the special product formulas for a cube of a binomial" ³ ` È q c r " ³ g 4 d F ¶ ¾ß X Í b " ³ Ä ' q 7 Ð @ ` À Ê o ¦ Ü J N õ ø¾¯ ã ¡ ` W 1 w 1 " ³ í L ` '¾® Ê T Æ ¶ Ú $ º¾Û § â M a § q 9 ë è ¾Ü¾® õ ø¾® » ´ ¾® ó ±¾® U º ` W 1 w ® Ͼ¯ Ú " ³ í L " ³ » É ¥ ðó ® ü ì ï c ÷ * 8 ú § ¬ ªé Ç ° ì Í ¤ Ô ® ¯ ø ³ ª ô · G $ ¨ W ù ì õ ì ù 8 ù ì õ ì ó 3 X Ç ì ä ï " ' Ä # J 3 & m Å C S Å!

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ƒ‰ƒCƒ" –³—¿ ƒCƒ‰ƒXƒg 3 ŒŽ-³44Cxx 2 ³ 2 e dx e C2 3 2 3xx 3 32 5 32 5 5 x x C ³ 4 ³2C xx 5 6) 5) 18 x ³Cxx e 6 4) 6) 5 xx x C ªº «» ³ ¬¼ 7 x eC 8 /2 2eCx 9 1 2 2 C 10 ln e e Cxx 11 2 12 21 ln 13 13 n x 14 Use dx u x 2 10) 4 e x u x SS ³³ S 15 2 22 ln 5 ln 2 (ln (ln 3 4ln 4) 2) 2)(ln xx dx d x x dx xx du ³ ³ ³ ;To simplify the above expressions, start by expanding the binomials Note that we can expand the (ab)^3 , (bc)^3 , and (ca)^3 using the special product formulas for a cube of a binomial

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4th under root of 81 = 3 or (3) 3rd under root of 216 = 6 5th under root of 32 = 2 under r0ot of 225 = 15 ⁴√81 8 (³√216) 15 (⁵√32) √225 = 3 (8 X 6) 15 X 2 15 = 0 ⁴√81 8 (³√216) 15 (⁵√32) √225 = (3) (8 X 6) 15 X 2 15 = 6C ³ s i l h z ´ t g n y µ q x m p f j k r C 3 " 9 3 !H istor c Train Garden (W ek nds) Pav il on of the Two Sis te r Th eH l is F ou ndat En riqu eAlfé z Sc ulpt r eGa d n C r o u s e l G a r d e n s A m u s m n t P a r k!j Anseman Oak McDonogh Oak Dueling ak!G W h e l F u n Bi k e s a n d B o a t s R e n ls ¯°±² ¯ ° ³ ´ ¯°³´ ¯ ° ³ ´ ¯°³´ ¯°³´ ¯°±²

Reverse Voltage ³ 5 ³ V ³ Operating/Storage Temperature ³ 40°C To 85°C ³ Lead Solder Temperature 2 ³ 260°C For 3 Seconds ³ Lead Solder Temperature 3 ³ 260°C For 5 Seconds ³ Downloaded from ArrowcomLet ux ln 2, dx x 2 2M417 Homework 3 Solutions Spring 04 (1) (a) For any subsets C 1,C 2 ⊂ A, show that f(C 1 ∪ C 2) = f(C 1) ∪ f(C 2) We must show that any element of f(C 1 ∪ C 2) is an element of f(C 1) ∪ f(C 2), and vice versaSo let y ∈ f(C 1 ∪ C 2) Then y = f(x) for some x ∈ C 1 ∪ C 2If x ∈ C

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Maharashtra State Board Class 8 Maths Solutions Chapter 5 Expansion Formulae Practice Set 53 Question 1 Expand i (2m – 5)³ ii (4 – p)³(− 25) (− 42) (− 42) − (−25) a train fare for partna to Delhi for 3 passenger in 840 rupees what will be the fare for 1 passenger x= 2 sint, y = cos 2t find dy by dxThe CX was the most important shortrange reconnaissance aircraft and dive bomber of the Finnish Air Force at the outbreak of the Winter War There were 29 of them in combat units, the "FransKalle" was slow but possessed a robust airframe, making it a useful asset the maximum dive speed was 540 km/h, which enabled it to break away from the

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2 ³ ² 7 ³ ² 39³ ² 27³ ² 16³ ² 8 ³ ² 3A³ ² 68³ ² 43³ ² 47³ ² 66³ ² 1A³ ² 60³ ² 5 ³ ² 28³ ² 23³ ² 72³ ² 42³ ² 93³ ² 24³ ² 9 ³ ² 6 ³ ² 3 ³ ² 53³ ² 18³ ² 54³ ² 32³ ² 2A³ ² 12³ ² 13³ ² ³ ² 44³ ² 40³ ² 33³ ² 11³ ² 1 ³ ² 43³ ² 2 ³ Meekwap Lake Foley Lake Deadman Lake McBrideFOLLOWING THE IDENTITY IF PQR=0,THEN P^3Q^3R^3= 3PQR We have here P=2a , Q=2B & R= 2C so (2a)³(2b)³(2c)³3(2a)(2b)(2c)(a b c)³= a³ b³ c³ 3 (a b) (b c) (a c) New questions in Math 5711/3% of 119 31/3% of 84 =?

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In arithmetic and algebra, the cube of a number n is its third power, that is, the result of multiplying three instances of n together The cube of a number or any other mathematical expression is denoted by a superscript 3, for example 2 3 = 8 or (x 1) 3 The cube is also the number multiplied by its square n 3 = n × n 2 = n × n × n The cube function is the function x ↦ x 3A II B I II C I III dd ³ ly none D 45 (NC) Consider the differential equation Let be the particular 2 1 3 solution to the given differential equation whose graph passes through the point 2, 12 Which of the following is tr dy x y y f x dx ue at the point 2, 12 on the graph of ?C x g y y 3 2 g y 3 2 y 1 2 l 1 1 9 y 4 dy portion School University of California, Berkeley;

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C K 1 4 ¨ ³ ² ´ Ô Í g ô Û Ô ® ¸ È Ç ¤ Ü u â 3 ñ 8 · ¨ b ¸ t3 3 Ç ° ± ³ Ó Ç ¢ u ¢ ø Ã · * í ¸ t9GD e ° ¸ ç ï ÿ 3 ´ ³ Ó Ç ¢ £ 9GD e ° ¸ t Å ´ Ñ ¬ ¯ ¸ t / c ´ b * í ¾ & Õ Ô & Ñ Ó Ç ¢ u 2&( ° ¸ Ä Ê È · b Æ ± ¯ F ¯ Ó Ç ¢ uFOLLOWING THE IDENTITY IF PQR=0,THEN P^3Q^3R^3= 3PQR We have here P=2a , Q=2B & R= 2C so (2a)³(2b)³(2c)³3(2a)(2b)(2c)% 8 ´ Ë ½ ¬ ¨ Ó ° ¢ c ¡ Í » t ó ³ ² · T ´ ¥ » u < Í ® ± Ø

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